What is the value of (2a+b)/(a+b)? (1) 3a/(a+b) = 7 (2) a+b = 3
Solution:
3a/(a+b)=7
=>a/a+b=7/3
=> 1+a/a+b=1+7/3
=>2a+b/a+b=10/7
1 is sufficient It's evident that 2 is not by itself sufficient. Answer is A.
Is |x+y| = 5? 1) |x| = 3 2) |y| = 2
Solution:
x+y = -5 or +5
1. x = -3 or 3 => insuff
2. y = -2 or 2 => insuff
together still insuff since |x+y| <= |x| + |y|
Dose the integer K has a factor p such that 1<p<K? 1) K>4! 2) 13!+2<k<13!+13
Solution:
A prime number has exactly two factors: itself and 1. By definition, it cannot have a factor p that is between itself and 1. A non-prime number, on the other hand, that is greater than 1 will have a factor between itself and 1 (again, by definition). So I can answer this question if I know whether k is prime. (1) Just tells me that k>24. There are prime numbers and non-prime numbers greater than 24, so that's not useful. (2) For any sum, if the two numbers in that sum have a common factor, that factor will also be a factor of the sum. E.g., 2 + 4 = 6. 2 is a factor of 2 and 2 is a factor of 4. Therefore, 2 will also be a factor of 6.
Answer is B.
Solution:
It's intuitive that either alone is not sufficient, so lets think about both statements together. Lets label some angles here: Let angles QRS=y, RQS=QSR=a, STU=z, UST=TUS=b. Now, y+z=90 because triangle RPT is a right triangle. We observe that y=180-2a and z=180-2b. So 180-2a+180-2b=90, which simplifies to 270-2(a+b)=0. We also observe that a+b+x=180, so a+b=180-x. Then 270-2(180-x)=0, and x=45. So the answer is C.
If arc QR is a semicircle and PQRS is a rectangle with QR > RS, what is the perimeter of the flower bed? (1) The perimeter of rectangle PQRS is 28 feet. (2) Each diagonal of rectangle PQRS is 10 feet long.
Solution:
Lets assume PS = QR = l RS = QP = w We should find l and w to solve this. 1 - Insufficient. All we know is 2(l + w) = 28 2 - insufficient. All we know is l^2 + w^2 = 100. Cannot solve for l or w. Using 1 and 2, we have 2 equations with 2 variables. So, a solution should exist and hence is sufficient. Sub l = 14 - w 196 + w^2 - 28w + w^2 = 100 w^2 - 14w + 48 = 0 w = 8 or 6 We are given that l > w and so we know what l is. Perimeter of the flower-bed can hence be computed.
Answer is C
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Solution:
3a/(a+b)=7
=>a/a+b=7/3
=> 1+a/a+b=1+7/3
=>2a+b/a+b=10/7
1 is sufficient It's evident that 2 is not by itself sufficient. Answer is A.
Is |x+y| = 5? 1) |x| = 3 2) |y| = 2
Solution:
x+y = -5 or +5
1. x = -3 or 3 => insuff
2. y = -2 or 2 => insuff
together still insuff since |x+y| <= |x| + |y|
Dose the integer K has a factor p such that 1<p<K? 1) K>4! 2) 13!+2<k<13!+13
Solution:
A prime number has exactly two factors: itself and 1. By definition, it cannot have a factor p that is between itself and 1. A non-prime number, on the other hand, that is greater than 1 will have a factor between itself and 1 (again, by definition). So I can answer this question if I know whether k is prime. (1) Just tells me that k>24. There are prime numbers and non-prime numbers greater than 24, so that's not useful. (2) For any sum, if the two numbers in that sum have a common factor, that factor will also be a factor of the sum. E.g., 2 + 4 = 6. 2 is a factor of 2 and 2 is a factor of 4. Therefore, 2 will also be a factor of 6.
Answer is B.
Solution:
It's intuitive that either alone is not sufficient, so lets think about both statements together. Lets label some angles here: Let angles QRS=y, RQS=QSR=a, STU=z, UST=TUS=b. Now, y+z=90 because triangle RPT is a right triangle. We observe that y=180-2a and z=180-2b. So 180-2a+180-2b=90, which simplifies to 270-2(a+b)=0. We also observe that a+b+x=180, so a+b=180-x. Then 270-2(180-x)=0, and x=45. So the answer is C.
If arc QR is a semicircle and PQRS is a rectangle with QR > RS, what is the perimeter of the flower bed? (1) The perimeter of rectangle PQRS is 28 feet. (2) Each diagonal of rectangle PQRS is 10 feet long.
Solution:
Lets assume PS = QR = l RS = QP = w We should find l and w to solve this. 1 - Insufficient. All we know is 2(l + w) = 28 2 - insufficient. All we know is l^2 + w^2 = 100. Cannot solve for l or w. Using 1 and 2, we have 2 equations with 2 variables. So, a solution should exist and hence is sufficient. Sub l = 14 - w 196 + w^2 - 28w + w^2 = 100 w^2 - 14w + 48 = 0 w = 8 or 6 We are given that l > w and so we know what l is. Perimeter of the flower-bed can hence be computed.
Answer is C
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