For every integer k from 1 to 10,inclusive,the kth term of a certain sequence is given by (-1)^k+1 * (1/2^k).If T is the sum of the 1st 10 terms in the sequence then T is, a)Greater than 2
b)between 1 and 2
c)between ½ and 1
d)between ¼ and ½
e)less than ¼
Solution:
Kth term of a sequence is = Rk = (-1)^k+1 * (1/2^k)
R1 = (-1)^2 * (1/2)^1 = 1/2
R2 = (-1)^3 * (1/2)^2 = -1/4 similarly,
R3= 1/8, R4 = -1/16 etc
So sum of 1st 10 terms in the sequence = S = 1/2 - 1/4 + 1/8 - 1/16 + 1/32 - 1/64 +1/128 etc up to the 10th term ( there will be total of 11 terms as S is inclusive of 1st and 10 term)
S = 1/2 +(- 1/4 + 1/8) + (- 1/16 + 1/32) etc ( there will be a total of 5 pairs like this as the sequence has 11 terms. )
S = 1/2 -1/8 -1/32 etc
If we sum up the negative terms
1/8 + 1/32 +.... we can see that sum is greater than 1/8 but less than 1/4 ( as 1/32+1/128 etc <1/8)
So the sum is greater than 1/2-1/4 =1/4 but less than 1/2 as we are subtracting 1/8 + 1/32 from 1/2 Hence the sum is between 1/2 and 1/4
Answer is D
b)between 1 and 2
c)between ½ and 1
d)between ¼ and ½
e)less than ¼
Solution:
Kth term of a sequence is = Rk = (-1)^k+1 * (1/2^k)
R1 = (-1)^2 * (1/2)^1 = 1/2
R2 = (-1)^3 * (1/2)^2 = -1/4 similarly,
R3= 1/8, R4 = -1/16 etc
So sum of 1st 10 terms in the sequence = S = 1/2 - 1/4 + 1/8 - 1/16 + 1/32 - 1/64 +1/128 etc up to the 10th term ( there will be total of 11 terms as S is inclusive of 1st and 10 term)
S = 1/2 +(- 1/4 + 1/8) + (- 1/16 + 1/32) etc ( there will be a total of 5 pairs like this as the sequence has 11 terms. )
S = 1/2 -1/8 -1/32 etc
If we sum up the negative terms
1/8 + 1/32 +.... we can see that sum is greater than 1/8 but less than 1/4 ( as 1/32+1/128 etc <1/8)
So the sum is greater than 1/2-1/4 =1/4 but less than 1/2 as we are subtracting 1/8 + 1/32 from 1/2 Hence the sum is between 1/2 and 1/4
Answer is D
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